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6x^2=-36x+240
We move all terms to the left:
6x^2-(-36x+240)=0
We get rid of parentheses
6x^2+36x-240=0
a = 6; b = 36; c = -240;
Δ = b2-4ac
Δ = 362-4·6·(-240)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-84}{2*6}=\frac{-120}{12} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+84}{2*6}=\frac{48}{12} =4 $
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